Edit2: Solved! Thank you all! 🥰 I was supposed to put quotation marks around the command argument variable/substitute within the script, as in scanimage -d [device] –format=png -p -o “$1”
Edit: turns out it’s not the accented character, but the whitespace character in front of július.png, since the script doesn’t accept julius.png either.
#!/bin/bash
# name of the script is SCAN.bash
scanimage -d [device] --format=png -p -o $1
I have tried ’ ', " " and to escape it with \
./SCAN 'anyu 1988 július.png'
./SCAN "anyu 1988 július.png"
./SCAN anyu\ 1988\ július.png
But it throws argument without option. It works fine if I type it out instead of scripting.
The target language is Hungarian and I have generated the necessary locale.
If there is whitespace in the filename, when you pass it to the script you need to escape it or wrap it in quotes. And then you need to put quotes around the variable in the script that reads the parameters.
From what you posted, you aren’t including the space in the filename inside the quotes
Put the $1 in quotes in the script.
-o "$1"?Thanks! Solved! 😁
Shellcheck can help spotting such mistakes: https://www.shellcheck.net/
Sic! What an awesome resource! Thanks! 😊
ahhh … found your problem: Put double quotes around the $1 in the bash script: scanimage -d [device] --format=png -p -o “$1”
Thanks! 😃
It does, bash uses your locale and if the umlauts are displayed correctly it is set to utf-8 or similar. Your other optiones aren’t parsed correctly
` #!/usr/bin/env bash
filename=“$1” angle=“$2” resolution=“$3” `
Didn’t cross my mind to put the quotes in the scrip 🤣 Thanks!
If there is whitespace in the file name then you need whitespace inside the quotes, or escape the whitespace at the beginning of the filename with backslash-space
![[SOLVED] Any way to make commands in bash scripts in the Linux terminal accept whitespace characters?](https://piefed.cdn.blahaj.zone/posts/dh/uX/dhuXsmM7hkJYhAU.jpg){kind=link}